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In considering this idea, it is apparent that the concept of the inverse square relationship as proposed by Newton remains predominant. The routes of this, I believe, can be logically associated with an electromagnetic phenomenon for the following reasons:

      The same inverse square effect of force over distance applies to permanent and electromagnets. 

      Intensity of light and other forms of radiation over distance also follows this relationship.

      The ratio between the increase in radius and surface area of a sphere also adheres to the same relationship.

 In considering the surface area of a spherical mass, it is apparent that it provides the ‘window’ through which radiation can be emitted and absorbed. It therefore logically follows that the larger the surface area, the greater the exchange rate of such radiation.
It is also noticeable that the smaller the radius of the sphere, the greater the ratio of surface area to mass, such that it doubles with each halving of the radius. This is significant in that it gives an insight as to how combined radiative forces could be relatively large in comparison to the size of minute particles, and in considering gravity to be a radiative force, it is obvious to make an assessment as to how strong such bonds might be. Indeed, I believe it might account for the atomic and sub atomic forces we currently distinguish as being of a completely separate origin.

A table of figures below demonstrates the relationship between the radius, surface area and volume of spheres, where ‘e’ denotes Earth and ‘m’ the moon. Other than the inclusion of the earth at 3.67r and the 3.0r, the radii are consecutively doubled.

  RADIUS (r)

    0.0625
    0.125
    0.25
  0.50
m 1.0
    2.0
    3.0
e 3.67
  4.0
    8.0
  16.0

  SURFACE AREA (sa)

        0.04906
        0.1875
        0.75
        3.0
      12.0
      48.0
    113.04
    161.6
    192.0
    768.0
  3072.0

  VOLUME (v)

       0.00102
      0.00781
      0.0625

      0.5
       4.0
    32.0
    113.04
    197.72
  256.0
  2048.0
16384.0

    sa/v

  48
  24
  12
    6

    3
    1.5
    1.0
    0.817
    0.75
    0.375
    0.1875

It is of mathematical interest that when the radius is 3, the surface area and volume have the same value.
Please note: to better demonstrate the equivalence relationship, π has been rounded down to 3.